Search pattern in 2d char arrays in C

#include <stdio.h>


int main(){

char a[]={'a','b','c'};
char *b[]={

/*0*/"hello",
/*1*/"abby",
/*2*/"cheeze",
/*3*/"ball",
/*4*/"cats"
      };
/* frist figure out how to get
   length of 2d array char*/
int sc=0;
for (int i=0;i<5;i++){
      sc=strlen(b[i]);
    printf("strlen *b[%d]=%lu\n",
     i,strlen(b[i]));
    }
printf("\n");
/* then figure out how to
  iterare the each word */
 for(int i=0;i<5;i++){
    sc=strlen(b[i]);
    for(int k=0;k<sc;k++){
       printf("%c ",b[i][k]);
    }
  printf("\n");
 }
/* now figure out how to use
   a search string of a single
   char to find the matching
   letter in each word */
/* get length of each word
   2d char array*/
 for(int i=0;i<5;i++)
 {
    sc=strlen(b[i]);
   /* search pattern */
   for(int e=0;e<3;e++)
   {/* iterate each letter of
       word */
     for(int k=0;k<sc;k++)
     { /*check search pattern
         againt each each char
         in string */
          if(a[e]==b[i][k])
          {
             printf("\nfound %c=%c\n"
             "word is: %s\n",
              a[e],b[i][k],b[i]);
          }
      }
    }
  printf("\n");
 }

return 0;
}