findDuplicateSector.py

# This script reads a reference sector from the partition, and then starting at
# startSector looks for an identical sector. If one isn't found by the time it
# gets to lastSector it will give up.
#
# This script is really slow (though gets close to my HDD's maximum transfer
# rate, so at least it's efficient), if you have any idea where the copied
# sector might be, use that information and save yourself some time!

refSector   = 1685403600 # <- Reference sector           EDIT THIS!
startSector = 1685403601 # <- Sector to start comparison EDIT THIS!
endSector   = 2000000000 # <- Sector to end comparison   EDIT THIS!

compareSector = startSector

bytesPerSector = 512

# Open the partition in binary, read only mode
ntfspartition=open("/dev/sda3",'rb')

# Read data in refSector
ntfspartition.seek(refSector*bytesPerSector,0)
refData=ntfspartition.read(1*bytesPerSector)
print("Data in reference sector is:\n\n" + nData + "\n\n")

# Read data at startSector
ntfspartition.seek(startSector*512,0)
compareData=ntfspartition.read(1*bytesPerSector)

print("Starting comparison with sector " + str(startSector))

# Loop through until we find an identical sector or we get to endSector
while ((refData != compareData) and (compareSector <= endSector)):
    compareSector += 1
    compareData = ntfspartition.read(512)
    if (( compareSector % 2097152) == 0):
        print("Offset: " + str(m/2097152) + " GiB, current sector: " + str(m))

# Close the 'file'
ntfspartition.close()

# Tell the user the outcome...
if (compareSector == (endSector+1)):
    print("Couldn't find any sector matching reference sector :(.")
else:
    print("Sector " + compareSector + " matches the reference sector! Yay!")