KatjaJu

#include <stdio.h>
#include <stdlib.h>

int main( int argc, char **argv )
{
    int i = 0;
    int j = 0;
    int maatriks[5][5];

    int max = 0;
    int min = 0;

    for( i = 1; i <= 5; i++ )
    {
        for( j = 1; j <= 5; j++ )
        {
            maatriks[i][j] = i * j;
        }
    }

    for( i = 1; i <= 5; i++ )
    {
        for( j = 1; j <= 5; j++ )
        {
            maatriks[i][j] = i * j;

            printf("%d\t", maatriks[i][j]);
        }
        printf("\n");
    }

    for( i = 1; i <= 5; i++ )
    {
        for( j = 1; j <= 5; j++ )
        {
            // Находим чётный максимум на главной диагонали
            if( i == j && 0 == maatriks[i][j]%2 )
            {
                if( max > maatriks[i][j] )
                {
                    max = maatriks[i][j];
                }
            }
        }
    }

    printf("Here is even max = %d from main diagonal.\n", max);

    return 0;
}