Reverse Function

int rever(int n) {
    int len = floor(log10(n)) +1 ;
    int na[len];
    int x;
    for (x=0;x<len;x++) {
        na[x] = n%10;
        n=n/10;
    }
    int number=0;

    for (x=0;x<len;x++) {
        number = number + na[x] * pow(10,(len-x-1));
    }
    return number;
}