Return number of even digits in integer - C#

        // Return numbers of even digits in n
        public static int NumEvenDigits(int n)
        {
            // counter for even numbers
            int count = 0;

            // 0 is a even number so return 1;
            if (n == 0)
            {
                return 1;
            }

            while (n != 0)
            {
                // if last digit of n is even, add 1 to count
                if (Math.Abs(n % 10)%2 == 0)
                {
                    count++;
                }
                // remove last digit from n
                n /= 10;
            }
            return count;
        }