#include <ctype.h>
#include <stdbool.h>

#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <sys/mman.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <unistd.h>
#include <errno.h>
#include <time.h>

#include "plugin_api.h"

static char *g_lib_name = "libavg.so";

static char *g_plugin_purpose = "Check whether two strings are anagram of each other";

static char *g_plugin_author = "Author";

#define NO_OF_CHARS 256

/* function to check whether two strings are anagram of
   each other */
bool areAnagram(char* str1, char* str2)
{
    // Create 2 count arrays and initialize all values as 0
    int count1[NO_OF_CHARS] = { 0 };
    int count2[NO_OF_CHARS] = { 0 };
    int i;

    // For each character in input strings, increment count
    // in the corresponding count array
    for (i = 0; str1[i] && str2[i]; i++) {
        count1[str1[i]]++;
        count2[str2[i]]++;
    }

    // If both strings are of different length. Removing
    // this condition will make the program fail for strings
    // like "aaca" and "aca"
    if (str1[i] || str2[i])
        return false;

    // Compare count arrays
    for (i = 0; i < NO_OF_CHARS; i++)
        if (count1[i] != count2[i])
            return false;

    return true;
}

/* Driver code*/
int main()
{
    char str1[] = "geeksforgeeks";
    char str2[] = "forgeeksgeeks";

    // Function Call
    if (areAnagram(str1, str2))
        printf("The two strings are anagram of each other");
    else
        printf("The two strings are not anagram of each "
               "other");

    return 0;
}

static int g_po_arr_len = sizeof(g_po_arr)/sizeof(g_po_arr[0]);



int plugin_process_file(const char *fname,
        struct option in_opts[],
        size_t in_opts_len) {

    // Return error by default
    //int ret = -1;     // Это должно быть, но в данном случае без этого можно обойтись. В ваших лабораторных эта строка быть должна!

    // Pointer to file mapping
    //unsigned char *ptr = NULL;  //Тоже нужная строчка - при правильной реализации (с точки зрения задания).

    char *DEBUG = getenv("LAB1DEBUG");

    if (!fname || !in_opts || !in_opts_len) {
        errno = EINVAL;
        return -1;
    }

    if (DEBUG) {
        for (size_t i = 0; i < in_opts_len; i++) {
            fprintf(stderr, "DEBUG: %s: Got option '%s' with arg '%s'\n",
                g_lib_name, in_opts[i].name, (char*)in_opts[i].flag);
        }
    }

    int leng = 0;
    int got_leng = 0;
    int saved_errno = 0;



        #define OPT_CHECK(opt_var, is_double) \
    if (got_##opt_var) { \
        if (DEBUG) { \
            fprintf(stderr, "DEBUG: %s: Option '%s' was already supplied\n", \
                g_lib_name, in_opts[i].name); \
        } \
        errno = EINVAL; \
        return -1; \
    } \
    else { \
        char *endptr = NULL; \
        opt_var = is_double ? \
                    strtod((char*)in_opts[i].flag, &endptr): \
                    strtol((char*)in_opts[i].flag, &endptr, 0); \
        if (*endptr != '\0') { \
            if (DEBUG) { \
                fprintf(stderr, "DEBUG: %s: Failed to convert '%s'\n", \
                    g_lib_name, (char*)in_opts[i].flag); \
            } \
            errno = EINVAL; \
            return -1; \
        } \
        got_##opt_var = 1; \
    }
    for (size_t i = 0; i < in_opts_len; i++) {
        if (!strcmp(in_opts[i].name, OPT_LENG_STR)) {
            OPT_CHECK(leng, 0)
        }
    else {
            errno = EINVAL;
            return -1;
        }
    }



    // C program to check if two strings
// are anagrams of each other