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- #include <stdio.h>
- #include <stdlib.h>
- #include <assert.h>
- #define NDEBUG
- void merge(int *arr, int l, int m, int r)
- {
- int i, j, k;
- int n1 = m - l + 1;
- int n2 = r - m;
- int L[n1], R[n2];
- for (i = 0; i < n1; i++)
- L[i] = arr[l + i];
- for (j = 0; j < n2; j++)
- R[j] = arr[m + 1+ j];
- i = 0;
- j = 0;
- k = l;
- while (i < n1 && j < n2)
- {
- if (L[i] <= R[j])
- {
- arr[k] = L[i];
- i++;
- }
- else
- {
- arr[k] = R[j];
- j++;
- }
- k++;
- }
- while (i < n1)
- {
- arr[k] = L[i];
- i++;
- k++;
- }
- while (j < n2)
- {
- arr[k] = R[j];
- j++;
- k++;
- }
- }
- void merge_sort(int *a, int p, int q) {
- int m;
- if(p < q)
- {
- m = (q+p)/2;
- merge_sort(a,p,m);
- merge_sort(a,m+1,q);
- merge(a,p,m,q);
- }
- }
- int main() {
- int numbers[] = {4, 9, 3, 1, 5, 7, 8, 6, 2};
- int expected[] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
- int i;
- int n = (int) (sizeof(numbers) / sizeof(int));
- merge_sort(numbers, 0, n-1);
- for (i = 0; i < n; i++) {
- printf("%d ",numbers[i]);
- }
- return 0;
- }
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