new-3x3.lua

-- pastebin get kZaXMD1Y

-- Normally for 3 recipes which compact 3 different ore reeds to ingots
-- you would use 3 crafters. This is the all-in-one solution.
-- One turtle for many 3x3 recipes.

-- Made by Konitor 2024

-- this turtle compacts 3x3 recipes. Originally made for a
-- ore reed farm which delivered different reeds to be compacted
-- to different ore ingots.
-- front chest = input chest. Make sure it has enough empty space
-- for the turtle to put back its contents.
-- down chest = output chest. Have a pipe system on it to always keep it empty.

-- you need a crafting turtle!!!!

-- crafted how many items so far?

crafted = 0

-- Check to see if I'm alright and ready for crafting

bCrafting = (peripheral.getType("left") == "workbench") or (peripheral.getType("right") == "workbench")
if not bCrafting then
  error("I want to be a crafty turtle! Craft me together with a crafting table.")
end

--Auto Label

if os.getComputerLabel() == nil then
  os.setComputerLabel("new-3x3")
end

-- copy this program to startup when its not "startup"

me = fs.getName( shell.getRunningProgram() )

if( me ~=  "startup") then
    print( "Overwriting startup with "..me )
    if( fs.exists("startup") ) then
        fs.delete("startup")
    end
    fs.copy( me, "startup" )
end


print( "Front chest = input" )
print( "Down chest = output" )
print( "Konitor 2024" )

-- first stack is selected after clearing

function cleartablebiggestfirst()

    local biggeststack = 0
    local biggestnum = 0

    for i=1, 16 do

        n = turtle.getItemCount( i )
        if n > biggestnum then
            biggeststack = i
            biggestnum = n
        end

    end

    if biggeststack > 0 then
        turtle.select( biggeststack )
        turtle.drop()
    end

    for i = 16, 1, -1 do
        turtle.select(i)
        turtle.drop()
    end

    sleep( 1 )

end

while true do

    cleartablebiggestfirst()

    docraft = true

    if turtle.suck(64) then

        n = turtle.getItemCount( 1 )
        r = n % 9
        anz = math.floor( n / 9 )

        if( anz > 0 ) then

            turtle.transferTo( 2, anz )
            turtle.transferTo( 3, anz )
            turtle.transferTo( 5, anz )
            turtle.transferTo( 6, anz )
            turtle.transferTo( 7, anz )
            turtle.transferTo( 9, anz )
            turtle.transferTo( 10, anz )
            turtle.transferTo( 11, anz )

        else

            docraft = false


        end

    else

        docraft = false

    end


    if docraft then

        turtle.craft( anz )
        -- drop rest of slot 1 back to source chest

        if r == 0 then
        -- Slot 1 contains crafted item
        turtle.dropDown()
        else
        -- Slot 1 contains input item - drop it back
        turtle.drop()
        end

        -- drop crafted items into target chest
        turtle.select(2)
        turtle.dropDown()

        crafted = crafted + anz

        print( "crafted " .. crafted .. " items")

    else

        cleartablebiggestfirst()

        for i = 1, 16 do
            turtle.suck()
        end

        cleartablebiggestfirst()

    end

end