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Ian mito

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May 24th, 2017
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C 1.46 KB | None | 0 0
  1. #include <stdio.h>
  2. #include <stdlib.h>
  3. #include <math.h>
  4.  
  5. int main()
  6. {
  7.     /*int vetor [8];
  8.     int i;
  9.     int num_maior_30=0, soma_30=0, soma_total=0;
  10.  
  11.  
  12.    for (i=0; i<8; i++)
  13.     {
  14.         scanf("%d",&vetor[i]);
  15.         soma_total+= vetor [i];
  16.  
  17.         if (vetor [i]>30)
  18.     {
  19.         soma_30+=vetor[i];
  20.         num_maior_30++;
  21.     }
  22.  
  23.     }
  24.  
  25.     printf("%d - %d - %d ",num_maior_30, soma_30, soma_total);
  26.  
  27.  
  28.     return 0;*/
  29.     /*char a[5]={'a','b','c','d','e'};
  30.     int i;
  31.     for(i = 4;i>=0;i--)
  32.     {
  33.         printf("%c",a[i]);
  34.     }*/
  35.  
  36.     int vetor[5]={1,2,3,4,5}; int vetor2[5];
  37.     int i;
  38.     for(i=0;i<5;i++)
  39.     {
  40.         vetor2[i] = pow(vetor[i],3);
  41.         printf("%d\n",vetor2[i]);
  42.     }
  43.  
  44.  
  45.  
  46. }
  47.  
  48.  
  49.  
  50.  
  51.  
  52.  
  53.  
  54.  
  55.  
  56.  
  57.  
  58.  
  59.     /*char ele1,ele2,ele3,ele4,ele5,ele6,ele7,ele8;
  60.     int n_ele1,n_ele2,n_ele3,n_ele4,n_ele5,n_ele6,n_ele7,n_ele8,mol1,mol2,mol3,mol4,x,y;
  61.     do{
  62.     scanf("%d%c%d%c%d + %d%c%d%c%d -> %d%c%d%c%d + %d%c%d%c%d",&mol1,&ele1,&n_ele1,&ele2,&n_ele2,&mol2,&ele3,&n_ele3,&ele4,&n_ele4,&mol3,&ele5,&n_ele5,&ele6,&n_ele6,&mol4,&ele7,&n_ele7,&ele8,&n_ele8);
  63.  
  64.     x = (mol1 * n_ele1) + (mol1 * n_ele2) + (mol2 * n_ele3) + (mol2 * n_ele4);
  65.     y = (mol3 * n_ele5) + (mol3 * n_ele6) + (mol4 * n_ele7) + (mol4 * n_ele8);
  66.     if(x==y)
  67.     {
  68.         printf("O balanceamento esta correto\n");
  69.  
  70.     }else
  71.     {
  72.         printf("O balanceamento esta incorreto\n");
  73.  
  74.     }
  75.     }while(mol1!=0 && mol2 !=0 && mol3 != 0);*/
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