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Jan 22nd, 2018
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  1. double f(double x)
  2. {
  3.     x = (x * x) + (x - 1);
  4.     return (x);
  5. }
  6.  
  7. void    f(double *x)
  8. {
  9.     *x = (*x * *x) + (*x - 1);
  10. }
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