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OR-struktura3

Sep 5th, 2015
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C 0.76 KB | None | 0 0
  1. #include <stdio.h>
  2. #include <stdlib.h>
  3.  
  4. struct grad {
  5. char naziv[20];
  6. int broj_stanovnika;
  7. };
  8.  
  9. int length (char *s) {
  10.     int d=0;
  11.     while (*(s++)!='\0') d++;
  12.     return d;
  13. }
  14.  
  15. int SlovoA (char *s) {
  16.     int i;
  17.     for (i=0; i<length(s); i++)
  18.     {  if (s[i]=='a' || s[i]=='A') return 1;
  19.     }
  20.     return 0;
  21. }
  22.  
  23.  
  24.  
  25. int BrStanovnika (struct grad *niz, int vel) {
  26.     int i, suma=0;
  27.     for (i=0; i<vel; i++) {
  28.             if (SlovoA(niz[i].naziv)) suma+=niz[i].broj_stanovnika;
  29.     }
  30.     return suma;
  31. }
  32.  
  33. int main () {
  34.     struct grad niz[5]={{"Visoko",2011},{"Gradacac",400},{"Olovo",1234},{"Tuzla",200},{"Paris",100}};
  35.     printf("Broj stanovnika u gradovima koji imaju bar jedno slovo a u imenu: %d", BrStanovnika(niz,5));
  36.     return 0;
  37. }
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