Time conversion

#include<stdio.h>

int main()
{
    char time[10];

    int i, frst_dgit, scnd_dgit, temp;

   scanf("%s", time);

    if(time[8] == 'P' && time[9] == 'M')
    {
        if(time[0] == '1' && time[1] == '2')
        {
            for(i = 0; i < 8; i++) printf("%c", time[i]);

            ///in 24 hour format we don't need last two character PM or AM, so conduct the loop until 7th index
        }
        else
        {
            scnd_dgit = time[1] - '0';
            //convert the character into integer, first two character indicates hour and that the things we have to convert into 24 hour format
            frst_dgit = time[0] - '0';
            //we have to add 12 with given hour, so we will add 1 with first digit of hour and 2 with second digit of hour
            if(scnd_dgit + 2 >= 10)
            {
                //if any value of second digit stands greater than 10 after adding two , we have to subtract 10 and add one with first digit
                time[1] = (scnd_dgit + 2 - 10)+ '0';

                ///as greater than 10  , we subtract it from second digit and add one with first digit

                time[0] =(frst_dgit + 1 + 1)+ '0';

                for(i = 0; i < 8; i++) printf("%c", time[i]);
            }
            else
            {
                time[1] = (scnd_dgit + 2) + '0';

                time[0] = (frst_dgit + 1) + '0';

                 for(i = 0; i < 8; i++) printf("%c", time[i]);
            }
        }
    }

    else if(time[8] == 'A' && time[9] == 'M')
    {
        if(time[0] == '1' && time[1] == '2')
        {
            time[0]=time[1]='0';
        //according to the condition in the question if 12:00:00AM then in 24 hour format it will be 00:00:00, so we made first two character zero
            for(i = 0; i < 8; i++) printf("%c", time[i]);
        }
        else
             for(i = 0; i < 8; i++) printf("%c", time[i]);
    }
    return 0;
}