Equal sum after extraction (a => a == firstList[i]) - Lists

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
//You will be given two integer lists on the first two lines (space-separated). Remove the elements in the first list from the elements //in the second list. If an element from the first list occurs more than once in the second list, remove all occurrences.
//After you remove the elements, check the sum of both lists. If the sum of both of them is equal, print “Yes. Sum: {sum}”. If not //print the absolute difference between the two lists in the format “No. Diff: {sum}”.

namespace Equal_Sum_After_Extraction
{
    class Program
    {
        static void Main(string[] args)
        {
            List<int> firstList = Console.ReadLine().Split().Select(int.Parse).ToList();
            List<int> secondList = Console.ReadLine().Split().Select(int.Parse).ToList();
            for (int i = 0; i < firstList.Count; i++)
            {
                for (int j = 0; j < secondList.Count; j++)
                {
                    if (firstList[i] == secondList[j])
                    {
                        secondList.RemoveAll(a => a == firstList[i]);
                    }
                }
            }

            int sumOfFirstList = firstList.Sum();
            int sumOfSecondList = secondList.Sum();
            if (sumOfFirstList == sumOfSecondList)
            {
                Console.WriteLine($"Yes. Sum: {sumOfSecondList}");
            }
            else
            {
                Console.WriteLine("No. Diff: {0}", Math.Abs(sumOfFirstList - sumOfSecondList));
            }
        }
    }
}