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roronoa

sum times comparaison à un max

Jul 17th, 2019
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  1. m=readline()
  2. N=readline()
  3. t=[3600,60,1]
  4. s=x=>{k=0;return x.split(':').reduce((a,b)=>a+t[k++]*b,0)}
  5. m=s(m)
  6. z=0
  7. for(i=0;i<N;i++)z+=s(readline())
  8. print(z<=m?true:false)
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