dmilicev

sqrt(a)+sqrt(b)=sqrt(2020)_v1.c

Sep 4th, 2020 (edited)
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  1. /*
  2.  
  3.     sqrt(a)+sqrt(b)=sqrt(2020)_v1.c
  4.  
  5.     Task:
  6.     sqrt(a)+sqrt(b)=sqrt(2020)
  7.     Find a and b.
  8.  
  9.  
  10.     You can find all my C programs at Dragan Milicev's pastebin:
  11.  
  12.     https://pastebin.com/u/dmilicev
  13.  
  14. */
  15.  
  16. #include <stdio.h>
  17. #include <math.h>
  18.  
  19. #define NUM_OF_ITERATIONS 1000
  20.  
  21. int main(void)
  22. {
  23.     int a, b, number_of_solutions=0;
  24.     double c = sqrt(2020);
  25.  
  26.     for(a=1; a<NUM_OF_ITERATIONS; a++)
  27.         for(b=1; b<NUM_OF_ITERATIONS; b++)
  28.         {
  29.             if( abs(c - sqrt(a) - sqrt(b))  < 0.1 )
  30.             {
  31.                 number_of_solutions++;
  32.                 printf("\n a = %d \t b = %d \n", a, b );
  33.                 printf(" \n %.16lf = sqrt(a) \n %.16lf = sqrt(b) \n  %.16lf = c-sqrt(a)-sqrt(b) \n", sqrt(a), sqrt(b), c - sqrt(a) - sqrt(b) );
  34.             }
  35.         }
  36.  
  37.     if( number_of_solutions == 0 )
  38.         printf("\n There is no such digits. \n");
  39.     else
  40.         printf("\n There are %d solutions. \n", number_of_solutions );
  41.  
  42.     return 0;
  43.  
  44. } // main()
  45.  
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