sqrt(a)+sqrt(b)=sqrt(2020)_v1.c

/*

    sqrt(a)+sqrt(b)=sqrt(2020)_v1.c

    Task:
    sqrt(a)+sqrt(b)=sqrt(2020)
    Find a and b.


    You can find all my C programs at Dragan Milicev's pastebin:

    https://pastebin.com/u/dmilicev

*/

#include <stdio.h>
#include <math.h>

#define NUM_OF_ITERATIONS 1000

int main(void)
{
    int a, b, number_of_solutions=0;
    double c = sqrt(2020);

    for(a=1; a<NUM_OF_ITERATIONS; a++)
        for(b=1; b<NUM_OF_ITERATIONS; b++)
        {
            if( abs(c - sqrt(a) - sqrt(b))  < 0.1 )
            {
                number_of_solutions++;
                printf("\n a = %d \t b = %d \n", a, b );
                printf(" \n %.16lf = sqrt(a) \n %.16lf = sqrt(b) \n  %.16lf = c-sqrt(a)-sqrt(b) \n", sqrt(a), sqrt(b), c - sqrt(a) - sqrt(b) );
            }
        }

    if( number_of_solutions == 0 )
        printf("\n There is no such digits. \n");
    else
        printf("\n There are %d solutions. \n", number_of_solutions );

    return 0;

} // main()