class -1 loop and array

#include<bits/stdc++.h>

using namespace std;

/*
1. Accept ‘m’ integer number and store them in an array arr[m],
2. then divide it into two arrays odd and even.
3. Write a program in the programming language C and
4.(1) display the contents of odd array and even array
5.(2) display the maximum number of arr[m]
6.(3) display the maximum number of even array
7.(4) display the multiplication value of minimum and maximum numbers of odd array.

*/

int main(){

   // # 1 task
  int array_size,odd_size=0,even_size=0,max_num_array = -1,max_num_even=-1,min_num_odd=10000,max_num_odd=-1;
  // array size taken
  printf("Enter arry size \n");
  scanf("%d",&array_size) ;

  //array creation
  int arr[array_size];

  printf("Enter arry elements \n");

    // array input taken
    int i;
    for(i=0;i<array_size;i++)
    {
        scanf("%d",&arr[i]);
        //odd-even check
        if(arr[i]%2==0)
            even_size++;
        else
            odd_size++;

        // maximum check
        if(arr[i]>max_num_array)
            max_num_array = arr[i];
    }



    // #2 task odd and even array can be of size different

    //even and odd array creation
    int even_array[even_size];
    int odd_array[odd_size];

    //value insertion

    int j,k;
    for(i=0,j=0,k=0;i<array_size;i++)
    {
        if(arr[i]%2==0)
        {
            even_array[k] = arr[i];
            // maximum check for even
            if(even_array[k]>max_num_even)
                max_num_even = even_array[k];
             k++;
        }
        else
        {
            odd_array[j] = arr[i];

            if(odd_array[j]>max_num_odd)
                max_num_odd = odd_array[j];
            if(odd_array[j]<min_num_odd)
                min_num_odd = odd_array[j];
            j++;
            }
    }

    // 10000+12222 = 5 sec 10 year smart human coder
    // 10-9 sec 1 sec  computer fast


    printf(" *** main array *** \n");
    for(i=0;i<array_size;i++)
    {
        printf("%d ",arr[i]);
    }

    printf("\n *** odd array ***\n");
    for(i=0;i<odd_size;i++)
    {
        printf("%d ",odd_array[i]);
    }

    printf(" \n ***  even array *** \n");
    for(i=0;i<even_size;i++)
    {
        printf("%d ",even_array[i]);
    }

    // maximuma array element print

    printf("\n maximum main array element is = %d ",max_num_array);
    printf("\n maximum even array element is = %d ",max_num_even);
    printf("\n the multiplication value of minimum and maximum numbers of odd array = %d",(max_num_odd*min_num_odd));


}

// index  - 0   1   2   3    4    5
// values - 50  30  55  56   79    80 - array use case - list  list id = array index  list value  = array value

// odd - 1,3 ,5,7,9 -9*1
// even -
/*

   #1  age theke jani- int arr[5] = {1,2,3,4,5};
   #2 user input dibe
    int array[5];
    array[0] = 10;
    array[1] = 10;
    array[2] = 10;
    array[3] = 10;
    array[4] = 10;

                 i
    main = 1,3,5,8,7,9,4
                j
    odd = 1,3,5
             k
    even = 8



    // nested if else

    if
        if
        else
    else if
        if
        else if
        else
    else


    // max or min checking logic
    arr = 1,2,3,4,5,7,1
    max_num_array = 7
    arr[i] = 1
*/