FizzBuzz in C by Wyatt

/* wyatt's C language fizzbuzz */
#include <stdio.h>
int i=1;
int main(){
        while(i<=100){
        /* print 'FizzBuzz' for numbers divisble by both */
                if(((double)i/3 == i/3) && ((double)i/5 == i/5)){
                        printf("FizzBuzz\n");
                }
        /* print 'fizz' for only numbers divisble evenly by only 3 */
                else if((double)i/3 == i/3){
                        printf("fizz\n");
                }
        /* print 'buzz' for only numbers divisible evenly by only 5 */
                else if ((double)i/5 == i/5){
                        printf("buzz\n");
                }
        /* print the number instead otherwise */
                else {
                        printf("%d\n",i);
                }
                i=i+1;
        }
}