Year_Month_Day_v2.c

// Version 2
// Program that accepts days as integer
// and display total numbers of years, month and days.
// The condition is that the year is 365 days and the month is 30 days.

#include<stdio.h>

void main(void)
{
    int n,mem_n,days,months, years; // variable declaration

// entering the number of days as an integer, n
    printf("\n Input an positive integer n = ");
    scanf("%d",&n);

// n changes over the course of the calculation,
// so we remember n in the number because we need to print the results at the end.

    mem_n=n;

// First, we find out how many whole years are contained in n.

    years = n/365;

// Then we find how many months are contained in the remaining n

    months = (n-years*365)/30;

// Then we find how many days are contained in the remaining n

    days = n - years*365 - months*30;


// display results

    printf("\n %d days is %d years %d months and %d days \n\n",mem_n,years,months,days);
}