Вариант 8. Таск 2

#include <stdio.h>
#include <math.h>

int main() {
    double a, b, c, status = scanf("%lf%lf%lf", &a, &b, &c) == 3 && a < b && (b - a) / c == (int)((b - a) / c);

    for (double x = a; x <= b && status; x += c) {
        printf("%lf | ", x);
        if (x <= -2 * M_PI)
            printf("%lf", exp(3 * sin(2 * x + 3)) + 2);
        else if (x <= 4 * M_PI)
            printf("%lf", (1 + x) * log(pow(cos(3 * x), 2) + 0.1));
        else
            printf("%lf", 2 * sin(1 + log(pow(x, 2) - 10 * M_PI)));

        printf("\n");
    }

    if (!status) printf("n/a");

    return 0;
}