CS1301xII Coding Problem 3.2.5

cafe = "Octane"
balance = 7.5

#You may modify the lines of code above, but don't move them!
#When you Submit your code, we'll change these lines to
#assign different values to the variables.

#Atlanta is full of great coffee places. Unfortunately, great
#coffee is usually expensive. The variables above will
#contain a balance and a cafe name. Below are the prices of
#a cup of coffee at each of three locations:
#
# - Octane: $6
# - Galloway: $5
# - Starbucks: $4
# - Revelator: $3
# - Dunkin: $2
#
#Add some code above that will print one of the following
#two messages depending on whether the value of balance is
#high enough to buy a cup of coffee at the given cafe.
#
# - If it is sufficient, print "With [balance] dollars, I
#   can buy coffee at [cafe]"
# - If it is not sufficient, print "With [balance] dollars,
#   I cannot buy coffee at [cafe]"


#Add your code here!

if (cafe=="Octane"):
    if (balance >= 6):
        print("With {} dollars, I can buy coffee at {}".format(balance, cafe))
    else:
        print("With {} dollars, I can not buy coffee at {}".format(balance, cafe))
elif (cafe=="Galloway"):
    if (balance >= 5):
        print("With {} dollars, I can buy coffee at {}".format(balance, cafe))
    else:
        print("With {} dollars, I can not buy coffee at {}".format(balance, cafe))
elif (cafe=="Starbucks"):
    if (balance >= 4):
        print("With {} dollars, I can buy coffee at {}".format(balance, cafe))
    else:
        print("With {} dollars, I can not buy coffee at {}".format(balance, cafe))
elif (cafe=="Revelator"):
    if (balance >= 3):
        print("With {} dollars, I can buy coffee at {}".format(balance, cafe))
    else:
        print("With {} dollars, I can not buy coffee at {}".format(balance, cafe))
elif (cafe=="Dunkin"):
    if (balance >= 2):
        print("With {} dollars, I can buy coffee at {}".format(balance, cafe))
    else:
        print("With {} dollars, I can not buy coffee at {}".format(balance, cafe))