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CS1301xII Coding Problem 3.2.5

CryptoJones Nov 29th, 2018 (edited) 173 Never
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  1. cafe = "Octane"
  2. balance = 7.5
  3.  
  4. #You may modify the lines of code above, but don't move them!
  5. #When you Submit your code, we'll change these lines to
  6. #assign different values to the variables.
  7.  
  8. #Atlanta is full of great coffee places. Unfortunately, great
  9. #coffee is usually expensive. The variables above will
  10. #contain a balance and a cafe name. Below are the prices of
  11. #a cup of coffee at each of three locations:
  12. #
  13. # - Octane: $6
  14. # - Galloway: $5
  15. # - Starbucks: $4
  16. # - Revelator: $3
  17. # - Dunkin: $2
  18. #
  19. #Add some code above that will print one of the following
  20. #two messages depending on whether the value of balance is
  21. #high enough to buy a cup of coffee at the given cafe.
  22. #
  23. # - If it is sufficient, print "With [balance] dollars, I
  24. #   can buy coffee at [cafe]"
  25. # - If it is not sufficient, print "With [balance] dollars,
  26. #   I cannot buy coffee at [cafe]"
  27.  
  28.  
  29. #Add your code here!
  30.  
  31. if (cafe=="Octane"):
  32.     if (balance >= 6):
  33.         print("With {} dollars, I can buy coffee at {}".format(balance, cafe))
  34.     else:
  35.         print("With {} dollars, I can not buy coffee at {}".format(balance, cafe))
  36. elif (cafe=="Galloway"):
  37.     if (balance >= 5):
  38.         print("With {} dollars, I can buy coffee at {}".format(balance, cafe))
  39.     else:
  40.         print("With {} dollars, I can not buy coffee at {}".format(balance, cafe))        
  41. elif (cafe=="Starbucks"):
  42.     if (balance >= 4):
  43.         print("With {} dollars, I can buy coffee at {}".format(balance, cafe))
  44.     else:
  45.         print("With {} dollars, I can not buy coffee at {}".format(balance, cafe))
  46. elif (cafe=="Revelator"):
  47.     if (balance >= 3):
  48.         print("With {} dollars, I can buy coffee at {}".format(balance, cafe))
  49.     else:
  50.         print("With {} dollars, I can not buy coffee at {}".format(balance, cafe))      
  51. elif (cafe=="Dunkin"):
  52.     if (balance >= 2):
  53.         print("With {} dollars, I can buy coffee at {}".format(balance, cafe))
  54.     else:
  55.         print("With {} dollars, I can not buy coffee at {}".format(balance, cafe))
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