Unix time to human readable

int main(){
    int months[] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31,
                     31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31,
                     31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31,
                     31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
    int time = 1330492354;
    int days = time / (60*60*24);
    time %= (60*60*24);
    int hours = time / (60*60);
    time %= (60*60);
    int minutes = time / (60);
    time %= (60);
    int seconds = time;

    int years = 1970;
    int i, d2 = days;

    for( i = 0; d2 > months[i%48]; ++i ){
        d2 -= months[i%48];
    }
    years += i / 12;
    int month = i % 12;
    char* monthstr[] = { "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December" };
    printf(" The date provided is %s %i, %i, and the time is %i:%i.%i\n", monthstr[month], d2+1, years, hours, minutes, seconds );
}