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Step8rother

Применение агрегирующих функций, задача 5

Step8rother
Jun 24th, 2023
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SQL 0.04 KB | Source Code | 0 0
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  1. SELECT COUNT(*) - COUNT(fax)
  2. FROM client;
Tags: sql Базовый SQL Агрегирующие функции Группировка и сортировка данных
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  • Step8rother
    Step8rother
    3 years
    # text 0.11 KB | 0 0
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    1. Посчитайте, сколько пропусков содержит поле fax из таблицы client.
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