strings-task5

"""
5. User enters a text string. You have to remove all “white symbols” and punctuation signs from it before further
processing. Then, you need to print out each unique symbol and it’s quantity within an input string.

Example:
Enter string: Hello world!

Result:

E: 1
n: 2
t: 2
e: 2
r: 3
s: 1
i: 1
g: 1
H: 1
l: 2
o: 2
w: 1
d: 1

5.1. Make this program case-insensitive.
"""
text=input("enter some text:")

#white spaces:
text=text.replace('\t','')
text=text.replace('\v','')
text=text.replace('\n','')
text=text.replace('\r','')
text=text.replace('\a','')
text=text.replace('\\','')
text=text.replace(' ','')

#punctuations:
text=text.replace(',','')
text=text.replace('.','')
text=text.replace(':','')
text=text.replace(';','')

#for ascii only:
# print("case sensitive case for ascii code:")
# counter = [i+65 for i in range(122)]
# for i in counter:
#     if chr(i) in text:
#         print(chr(i), ":", text.count(chr(i)))
#     else:
#        pass

print("case sensitive case for any encoding:")
symbols={}
for letter in text:
    if letter not in symbols.keys():
        symbols[letter] = 1
    else:
        symbols[letter] += 1
print(symbols)


#print("case insensitive case:")
#counter = [i+65 for i in range(26)]
#counter2=0
#for i in counter:
#    if (chr(i) in text) or (chr(i+32) in text):
#        counter2=text.count(chr(i))+text.count(chr(i+32))
#        print(chr(i),"or ", chr(i+32),":", counter2)
#    else:
#        pass

print("case insensitive case for any encoding:")
symbols={}
letter2=''
for letter in text:
    letter2=letter+','+letter.swapcase()
    letter3=letter.swapcase()+','+letter
    if (letter2 and letter3) not in symbols.keys():
        symbols[letter2] = 1
    elif (letter2 not in symbols.keys()) and (letter3 in symbols.keys()):
        symbols[letter3] += 1
    elif (letter3 not in symbols.keys()) and (letter2 in symbols.keys()):
        symbols[letter2] += 1
    else:
        pass
print(symbols)