C za djuru

//1. Zadatak
#include <stdio.h>
#include <math.h>

int main(int argc, char const *argv[])
{
    double y;
    for (int x = -4; x <= 4; x++) {
        if ( x < 0) {
            y = pow(x, 3) + pow(2, x);
        } else if ( x <= 1) {
            y = sin(pow(x, 3))+ cos(x);
        }
        else {
            y = sqrt(sin(3*x));
        }
        printf("Za vrednost argumenta x = %d funkcija ima vrednost y = %f\n", x, y);
    }
    return 0;
}

//2. Zadatak
#include <stdio.h>

double povrsina(int r) {
    return 4* 3.14 * r *r;
}

double zapremina(int r) {
    return 4/3 * 3.14 * r*r*r;
}
int main()
{
    double s = 0;
    int n;
    scanf("%d", &n);

    for (int i = 0; i < n; i++) {
        printf("Unesite podatke za %d. loptu\n", i+1);

        int r;
        scanf("%d", &r);
        s += povrsina(r);
        printf("Lopta broj %d sa poluprecnikom %d ima zapreminu %0.2f\n", i+1, r, zapremina(r));
    }
    printf("Ukupna pov lopti je %f\n", s);
    return 0;
}

//3. Zadatak
#include <stdio.h>
#include <time.h>
#include <stdlib.h>

int main()
{
    srand(time(NULL));

    int a1[20], a2[20], a3[20];
    int n1 = 0, n2 = 0, n3 = 0;

    int count = 1;
    int br = rand() % 10001;
    while (br != 100 && count < 20) {
        count ++;

        cJedinica = br % 10;
        cDesetica = (br / 10) br % 10;
        cStotina = (br / 100) br % 10;

        if(cJedinica + cDesetica + cStotina > 25)
            break;

        if(br < 10)
            a1[n1++] = br;
        else if (br < 100)
            a2[n2++] = br;
        else
            a3[n3++] = br;

        br = rand() % 10001;
    }

    printf("A1 = {");
    for (int i= 0; i < n1; i++) {
        printf("%d, ", a1[i]);
    }
    printf("}\n");


    printf("A2 = {");
    for (int i= 0; i < n2; i++) {
        printf("%d, ", a2[i]);
    }
    printf("}\n");


    printf("A3 = {");
    for (int i= 0; i < n3; i++) {
        printf("%d, ", a3[i]);
    }
    printf("}\n");
    return 0;
}
//4. Zadatak
int main()
{
    int mat[256][256];
    int n;

    printf("Unesite n\n");
    scanf("%d", &n);

    for (int i = 0; i < n; i++)
        for (int j = 0; j < n; j++) {
            if (i == 0 || (i == n-1  && j < n/2)|| j == 0 || j == n-1 || j == n / 2) {
                mat[i][j] = 1;
            }
            else
                mat[i][j] = 0;
        }

    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            printf("%d ", mat[i][j]);
        }
        printf("\n");
    }
    return 0;
}

//5. Zadatak
int main(int argc, char const *argv[])
{

    return 0;
}