02. Odd and Even Jumps25 July 2014 Evening

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
           // Software University  // primeren vhod
           //   3
           //    2
           //odd result = ( ( (+ 115 's' + 102 'f') * 119 'w' + 114 'r' + 117 'u' ) * 105 'i' + 101 'e' + 115 's' ) * 116 't' = 317362776 = 12EA9258 (hex)
            string[] input = Console.ReadLine()
           .ToLower()
           .Split(new string[] { " " }, StringSplitOptions.RemoveEmptyEntries);
            string processedInput = string.Join("", input);// za premahvane na razstoqniqta v masiv
            int oddJump = int.Parse(Console.ReadLine());
            int evenJump = int.Parse(Console.ReadLine());

            long oddResult = 0;
            long evenResult = 0;
            int currentJumpPos = 1;

            // Odd characters
            for (int i = 0; i < processedInput.Length; i += 2)// +2 za da mi preskacha bukvite po 1 i da vurvi po 0 2 4 6
            {
                long currentSymbolCode = (long)processedInput[i];
                if (currentJumpPos == oddJump)// za da mi umnojava togava smao kogato currentJumpPos = oddJump primer 3 = 3
                {
                    oddResult *= currentSymbolCode;
                    currentJumpPos = 1; // vrushtame pak na 1 za da se polu4i cikli4nosta ina4e to shte produlji da se natrupva
                }
                else
                {
                    oddResult += currentSymbolCode; // ako gorniqt if ne mi e veren vlizme v else i si pribavqme
                    currentJumpPos++; // uvelichavame currentJumpPos++ s 1 samo v else zashtoto ako e izvun if else statmanta shte go uvelichava vseki put i taka samo pri purvata poredica ot bukvi (+ 115 's' + 102 'f') * 119 she mi e 3 sled tova she go vurti na seki 2 puti pri purvite 3 zavurtaniq 1 zavurtane vliza v else i currentJumpPos mi e 2 na 2 zavurtane vliza v else i currentJumpPos mi e 3 na 3 zavurtane vliza v if izvurshva umnojenieto * i go vrushta na 1 no ako e izvun if/else steitmanta go natruva s 1 i stava 2 i pri 4 zavurtane ve4e e currentJumpPos 3 a to trqbva da e currentJumpPos 2
                }
                //currentJumpPos++;
            }

            currentJumpPos = 1;// vrushtame stoinostta na 1 za da moje da  si napravim pak sushtata ciklichnost
            // Even characters
            for (int i = 1; i < processedInput.Length; i += 2) // i= 1; za da moje da zima 1 3 5 7 even chislata
            {
                long currentSymbolCode = (long)processedInput[i];
                if (currentJumpPos == evenJump)
                {
                    evenResult *= currentSymbolCode;
                    currentJumpPos = 1;
                }
                else
                {
                    evenResult += currentSymbolCode;
                    currentJumpPos++;
                }
            }

            Console.WriteLine("Odd: {0:X}", oddResult);
            Console.WriteLine("Even: {0:X}", evenResult);
        }
    }
}