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ProstiBrohjevi

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Feb 19th, 2020
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C 0.31 KB | None | 0 0
  1. #include<stdio.h>
  2.  
  3. void prosti(int a)
  4. {
  5.     int i, i1, flag;
  6.     for(i=1;i<a;i++)
  7.      {
  8.         flag=0;
  9.         for(i1=2;i1<i;i1++)
  10.         {
  11.             if(i%i1==0)
  12.             {
  13.                 flag=1;
  14.                 break;
  15.             }
  16.         }
  17.         if(flag==0)
  18.             printf("Broj %d je prost broj",i1);
  19.      }
  20. }
  21. int main()
  22. {
  23.     int n;
  24.     scanf("%d",&n);
  25.     prosti(n);
  26.     return 0;
  27. }
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