Вариант 5. Таск 2

#include <stdio.h>
#include <math.h>

int main() {
    double a, b, c;
    int n;
    scanf("%lf%lf%d", &a, &b, &n);
    c = (b - a) / n;

    for (double x = a; x <= b; x += c) {
        printf("%lf | ", x);
        if (x <= -10)
            printf("%lf", 1 / (2 + sin(2  * x)));
        else if (x <= -2)
            printf("%lf", exp(-2 * x) * pow(cos(pow(x, 2) / 5), 2));
        else
            printf("%lf", (0.3 * x + 2) * sin(x / (pow(x, 2) + 5)));

        printf("\n");
    }

    return 0;
}