08. DigitAsWord

using System;

//Write a program that asks for a digit (0-9), and depending on the input, shows the digit as a word (in English). Print “not a digit” in case of invalid inut. Use a switch statement. Examples:
// |    d | result      |
// |    2 | two         |
// |    1 | one         |
// |    0 | zero        |
// |    5 | five        |
// | -0.1 | not a digit |
// |   hi | not a digit |
// |    9 | nine        |
// |   10 | not a digit |

class DigitAsWord
{
    static void Main()
    {
        try
        {
            byte digit = byte.Parse(Console.ReadLine());
            switch (digit)
            {
                case 0:
                    Console.WriteLine("zero"); break;
                case 1:
                    Console.WriteLine("one"); break;
                case 2:
                    Console.WriteLine("two"); break;
                case 3:
                    Console.WriteLine("three"); break;
                case 4:
                    Console.WriteLine("four"); break;
                case 5:
                    Console.WriteLine("five"); break;
                case 6:
                    Console.WriteLine("six"); break;
                case 7:
                    Console.WriteLine("seven"); break;
                case 8:
                    Console.WriteLine("eight"); break;
                case 9:
                    Console.WriteLine("nine"); break;
                default:
                    Console.WriteLine("not a digit"); break;
            }
        }
        catch (Exception)
        {
            Console.WriteLine("not a digit"); ;
        }
    }
}