Spiral Solution

Spiral Problem Solution:

class Solution(object):
    def spiralOrder(self, matrix):
        return matrix and [*matrix.pop(0)] + self.spiralOrder([*zip(*matrix)][::-1])

        #[[123][456][789]] -> []


        """
        explaination:
        the 'matrix and' makes sure the matric is not empty
        matrix.pop(0) removes ther first row (we want to add it back in the next step)
        [*matric.pop(0)] it makes an array without the first row (* in python turns an iterable into its constitutents)
        zip(*matrix)it splits the matrix into its rows and then combines them together in dfifrent order
        [::-1] reverses the amtric
        'self.spiralOrder' does keeps on doing it until there are no more elements in the list
        the + before the self.spiralorder adds back the first row. Like if it is [6,9,8,7,4,5], then it will add back the [1,2,3] to it
        the 'matric and [*matrix.pop(0)]' makes sure that after removing a row, the matrix isnt empty
        """