ComparingFloats

using System;
//Write a program that safely compares floating-point numbers (double) with precision eps = 0.000001. Note that we cannot directly compare two floating-point numbers a and b by a==b because of the nature of the floating-point arithmetic. Therefore, we assume two numbers are equal if they are more closely to each other than a fixed constant eps. Examples:

//Number a  Number b    Equal (with precision eps=0.000001) Explanation
//5.3   6.01    false   The difference of 0.71 is too big (> eps)
//5.00000001    5.00000003  true    The difference 0.00000002 < eps
//5.00000005    5.00000001  true    The difference 0.00000004 < eps
//-0.0000007    0.00000007  true    The difference 0.00000077 < eps
//-4.999999 -4.999998   false   Border case. The difference 0.000001 == eps. We consider the numbers are different.
//4.999999  4.999998    false   Border case. The difference 0.000001 == eps. We consider the numbers are different.


class ComparingFloats
{
    static void Main()
    {
        Console.Write("Enter a number: ");
        double a = double.Parse(Console.ReadLine());
        Console.Write("Enter a number: ");
        double b = double.Parse(Console.ReadLine());

        double eps = 0.000001;

        if (a > b)
        {
            if (a - b > eps)
            {
                Console.WriteLine("The two numbers are not equal with precision 0.000001");
            }
            else
            {
                Console.WriteLine("The two numbers are equal with precision 0.000001");
            }
        }
        else if (b < a)
        {
            if (b - a > eps)
            {
                Console.WriteLine("The two numbers are not equal with precision 0.000001");
            }
            else
            {
                Console.WriteLine("The two numbers are equal with precision 0.000001");
            }
        }

    }
}