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- b = [0 1 4 3;-1 5 6.06 -3]; % kontrolne tocke b
- c = [3 6 7 4.06;0 2 -2 -5]; %kontrolne tocke c
- ct = @(t)bezier(c,t);
- vzporednica = ct(1/3);
- y = vzporednica(2) %<-------- odgovor prva tocka
- bt = @(t)(-(1-t)^3+15*t*(1-t)^2+3*6.06*t^2*(1-t)-3*t^3 - y); % krviulja b, y koordinata
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