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- //Problem 8. Digit as Word
- //Write a program that asks for a digit (0-9), and depending on the input, shows the digit as a word (in English). Print “not a digit” in case of invalid inut. Use a switch statement.
- using System;
- class DigitAsWord
- {
- static void Main()
- {
- Console.Write("Please, enter some number:");
- int number = int.Parse(Console.ReadLine());
- switch (number)
- {
- case 0:
- Console.WriteLine("zero");
- break;
- case 1:
- Console.WriteLine("one");
- break;
- case 2:
- Console.WriteLine("two");
- break;
- case 3:
- Console.WriteLine("three");
- break;
- case 4:
- Console.WriteLine("four");
- break;
- case 5:
- Console.WriteLine("five");
- break;
- case 6:
- Console.WriteLine("six");
- break;
- case 7:
- Console.WriteLine("seven");
- break;
- case 8:
- Console.WriteLine("eight");
- break;
- case 9:
- Console.WriteLine("nine");
- break;
- default:
- Console.WriteLine("It's not a digit between 0 to 9");
- break;
- }
- }
- }
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