LCM C

// program to find LCM of 2 given numbers

#include <stdio.h>
#include<conio.h>

int gcd (int ,int );        //function declaration
int lcm (int ,int );

int main()
{
    int num1 = 0,num2 = 0, result = 0, cont = 0;

    do
    {
        printf("\nENTER 2 POSITIVE NUMBERS ");
        printf("\nENTER NUMBER 1 : ");
        scanf("%d",&num1);
        printf("ENTER NUMBER 2 : ");
        scanf("%d",&num2);

        result = lcm(num1,num2);
        printf("\nTHE LCM OF THE ENTERED NUMBERS IS : %d ", result);
        printf("\n\nDO YOU WANT TO CALCULATE AGAIN (1/0) :");
        scanf("%d",&cont);

    }while(cont==1);
    return 0;
}


// method to find gcd of 2 numbers
int gcd (int m1 , int m2)
{
    if(m1==0 || m2==0)
    {
        return 0;
    }
        do
        {
            if(m1 > m2)
            {
                m1 = m1 - m2;
            }
            else
            {
                m2 = m2 - m1;
            }
    }while(m1!=m2);

        return(m1);
}

// method that finds lcm of numbers
int lcm(int num1, int num2){

    int res = gcd(num1, num2);
    int lcm_num = (num1 * num2) / res;
    return lcm_num;
}
/******************************OUTPUT**********************************

ENTER 2 POSITIVE NUMBERS
ENTER NUMBER 1 : 12
ENTER NUMBER 2 : 14

THE LCM OF THE ENTERED NUMBERS IS : 84

DO YOU WANT TO CALCULATE AGAIN (1/0) :1

ENTER 2 POSITIVE NUMBERS
ENTER NUMBER 1 : 15
ENTER NUMBER 2 : 25

THE LCM OF THE ENTERED NUMBERS IS : 75

DO YOU WANT TO CALCULATE AGAIN (1/0) :0

F:\BLOG PROGRAMS\LCM>
*/