probability of finding 3 or 6 or 9 head

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
int main()
{
int j,count=0,limit,i=0,head,tail;
float y,answer,h=2.5;

printf("enter the limit amount");
scanf("%d",&limit);
//drawing head in head tails either 3 6 or 9 times
while(i<=limit)
{
i++;
head=0;
tail=0;
//toss 10 times
for(j=0;j<10;j++)
{
    //random number generated
y=(float)((rand()% 65535)/65535.0f)*10;
printf("%f\n",y);
//head if y <2.5
if (y<h)
{
head=head+1;
}
else
{

tail=tail+1;
}
}
//check prpob
if ((head==3) || (head==6) || (head==9))
{
count=count+1;
}
}
answer=(float)count/limit;
printf("the limit is= %d \n and the probability is = %f",limit,answer);
return 0;

}