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zadatak

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Mar 26th, 2019
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C 0.38 KB | None | 0 0
  1. int provera(int niz[], int k, int n) {
  2.     int povracaj = 0;
  3.     for (int i = 0; i < n; i++)
  4.     {
  5.         for (int  j = i+1; j < n; j++)
  6.         {
  7.             if (abs(niz[i] - niz[j]) == k) {
  8.                 povracaj = 1;
  9.                 break;
  10.             }
  11.         }
  12.     }
  13.     return povracaj;
  14. }
  15. int main(void) {
  16.    
  17.     int niz[10] = { 5,10,6,4,3 };
  18.     int n = 5;
  19.     int k = 0;
  20.     provera(niz, k, n) ? printf("Da") : printf("NE");
  21.  
  22.     return 0;
  23. }
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