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Telaryon
Mar 6th, 2017
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C
0.23 KB
| None
|
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int
main
(
)
{
double
sum
=
0
;
int
i
;
for
(
i
=
1
;
i
<=
1000
;
i
++
)
{
if
(
i
%
2
)
sum
+=
1.0
/
(
i
*
2
-
1
)
;
else
sum
-=
1.0
/
(
i
*
2
-
1
)
;
}
printf
(
"%.2lf"
,
sum
*
4
)
;
return
0
;
}
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