square pattern with cross v1.c

/*
    square pattern with cross v1.c

 Program by Debottam Das
 https://www.facebook.com/debottam.das.121

 Enter any odd number of rows: 11

 output is :

          *
        # * #
      # # * # #
    # # # * # # #
  # # # # * # # # #
* * * * * * * * * * *
  # # # # * # # # #
    # # # * # # #
      # # * # #
        # * #
          *

*/


#include<stdio.h>


void square_pattern_with_cross(int n)
{
    int i, j, s, s1=0, s2=0, s3;

    s  = n/2;
    s1 = s+1;
    s2 = s;
    s3 = s1;

    for(i=1; i<=((n/2)); i++)
    {
        for(j=1; j<=s1; j++)
        {
            if(j<=s && s!=0)
            {
                printf("  ");
            }
            else if (j == ((n/2)+1))
            {
                printf("* ");
            }
            else
            {
                printf("# ");
            }
        }
        s--;
        s1++;
        printf("\n");
    }

    for(i=1; i<=n; i++)
    {
        printf("* ");
    }

    printf("\n");

    s  = 1;
    s1 = (n/2)+(n/2);   // not s1 = n because of integer division !
    s2 = n/2;

    for(i=1; i<=s2; i++)
    {
        for(j=1; j<=s1; j++)
        {
            if(j<=s && s!=0)
            {
                printf("  ");
            }
            else if (j == ((n/2)+1))
            {
                printf("* ");
            }
            else
            {
                printf("# ");
            }
        }

        s++;
        s1--;

        printf("\n");
    }
}


void main(void)
{
    int number_of_rows;

    printf("\n Enter any odd number of rows: ");
    scanf("%d",&number_of_rows);

    printf("\n");

    if(number_of_rows %2 == 0)
    {
        printf("\n SORRY! With even numbers this pattern is not possible. \n");
        return 1;
    }

    square_pattern_with_cross(number_of_rows);


    return 0;
}