C - Return a new array via pointer

#include <stdio.h>
#include <stdlib.h>


char *newChar();

int main(){

    //This will print what is returned from *newChar() - Just for testing to see if it works :)
    printf("\n%s", newChar());


    char *b = malloc(3 * sizeof(char)); //This is the local var - Must use malloc for this to work - The "3" is the size of the char array
    b = newChar(); //This sets the local var to the return of *newChar()
    printf("\n%s", b); //Print out

}

//This will return a pointer
char *newChar(){

    char *a = malloc(3 * sizeof(char));

    a[0] = 'a';
    a[1] = 'b';
    a[2] = '\0';

    return a; //Since "a" was declared as a pointer, this is returning a pointer. Doing *a, would be the pointer of the pointer
}