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ndiv
GeeckoDev
Aug 30th, 2011
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int
nbDiviseurs
(
int
n
)
{
int
n_div
=
0
;
sqrt_n
=
sqrtf
(
n
)
;
for
(
i
=
2
;
i
<=
sqrt_n
;
i
++
)
{
if
(
n
%
i
==
0
)
n_div
+=
1
+
i
!=
n
/
i
;
}
return
n_div
;
}
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