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Feb 26th, 2020
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  1.     for (j = 2; j < 2 * n; ++j) {
  2.         for (i = 2 * n - 1; i >= j; --i) {
  3.             if (i & 1)
  4.                 d[i >> 1] = (d[i >> 1] - y[i >> 1]) / (x[i >> 1] - x[(i - j) >> 1]);
  5.             else
  6.                 y[i >> 1] = (y[i >> 1] - d[(i >> 1) - 1]) / (x[i >> 1] - x[(i - j) >> 1]);
  7.         }
  8.     }
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