Interval Max Overlap

class Solution {
    public int minMeetingRooms(int[][] intervals) {
        Arrays.sort(intervals, (a, b) -> a[0] - b[0]);
        PriorityQueue<Integer> pq = new PriorityQueue<>();
        int maxSize = 0, start = -1, end = -1;

        for (int[] i : intervals) {
            while (!pq.isEmpty() && pq.peek() <= i[0]) {
                if (pq.size() == maxSize) {
                    end = pq.peek(); // last active meeting's end before drop
                }
                pq.poll();
            }

            pq.offer(i[1]);

            if (pq.size() > maxSize) {
                maxSize = pq.size();
                start = i[0]; // track the start of the max overlap range
            }
        }

        // Handle case where the last interval is part of the max overlap
        if (pq.size() == maxSize) {
            end = pq.peek(); // final end if the max overlap lasts until the end
        }

        System.out.println("Max overlap was between " + start + " and " + end);
        return maxSize;
    }
}