digits_for_the_sum_of_three_numbers.c

/*

    digits_for_the_sum_of_three_numbers.c

    Find the values of x, y and z
    so that they can fulfill the given condition.

    Each digit x, y and z may have value between 0 to 9.

    xyx
    xyz
   +xzz
   -----
   1416


    You can find all my C programs at Dragan Milicev's pastebin:

    https://pastebin.com/u/dmilicev

    https://www.facebook.com/dmilicev

*/

#include <stdio.h>

int main(void)
{
    int x, y, z, solved = 0, sum = 1416;
    int num1, num2, num3;

    for(x=0; x<10; x++)
        for(y=0; y<10; y++)
            for(z=0; z<10; z++)
            {
                num1 = x*100 + y*10 + x;
                num2 = x*100 + y*10 + z;
                num3 = x*100 + z*10 + z;

                if( num1 + num2 + num3 == sum )
                {
                    solved = 1;
                    printf("\n x = %d , y = %d , z = %d \n", x,y,z);
                    printf("\n %5d ", num1);
                    printf("\n %5d ", num2);
                    printf("\n+%5d ", num3);
                    printf("\n---------");
                    printf("\n %5d \n", sum);
                }
            }

    if( !solved )
        printf("\n There is no such digits. \n");

    return 0;

} // main()