PetiCas (nizovi)

#include <stdio.h>
#include <stdlib.h>
#include "time.h"

void inc10(int *nPtr)
{
    *nPtr=*nPtr+10;
}

int ascending(int a, int b)
{
    return a>b;
}

int descending(int a, int b)
{
    return a<b;
}

void swap_elements(int* a, int* b)
{
    int temp=*a;
    *a=*b;
    *b=temp;
}

void sort(int* a,int n,int (*compare)(int,int))
{
    int i,j;
    for(i=0;i<n-1;i++)
    {
        for(j=i+1;j<n;j++)
        {
            if((*compare)(a[i],a[j])  )
            {
                swap_elements(&a[i],&a[j]);
            }
        }
    }
}

void popuniNiz( int * niz, int n)
{

    int i;
    for(i=0;i<n;i++)
        niz[i]=rand()%100;

}





int main()
{

    srand(time(0));





    int a=10;
    int* aPtr;
    aPtr=&a;

    printf("aPtr=%p\n  &a=%p\n",aPtr,&a);

    int b;
    b=*aPtr;
    printf("b=%d\n",b);

    printf("%p %p\n",*&aPtr,&*aPtr);
    *aPtr=100;
    printf("a=%d b=%d\n",a,b);

    int x=13;
    inc10(&x);
    printf("%d\n",x);

    int* tPtr=NULL;

/*
    int *const xPtr1=&x;
    xPtr1=&a; //mijenja vrijednost pokazivacu koji je konstanta
    *xPtr1=50;

    const int* xPtr2=&x;
    xPtr2=&a;
    *xPtr2=80; //mijenja vrijednost konstantne promjenjive

    const int *const xPtr3=&x;
    xPtr3=&a;
    *xPtr3=70;
*/

void (*fPtr) (int*);
fPtr=inc10;
    (*fPtr)(&x);
    printf("x=%d\n",x);

    int niz1[5]={23,45,3,65,11};
    int* nPtr=&niz1[0];
    printf("%p %p\n",nPtr,niz1);

    int i;
    for(i=0;i<5;i++)
    {
        printf("%4d",nPtr[i]);
    }
printf("\n");
printf("%p\n",nPtr+2);





    sort(niz1,5,ascending);
for(i=0;i<5;i++)
    {
        printf("%4d",*(nPtr+i));
    }
printf("\n");

int n;
scanf("%d",&n);
int* niz2=malloc(n*sizeof(int)); //aloricanje memorije na heap-u
popuniNiz(niz2,n);

for(i=0;i<n;i++)
    {
        printf("%4d",niz2[i]);
    }
printf("\n");

int r,c;
scanf("%d",&r);
scanf("%d",&c);

int** mat=malloc(r*sizeof(int*));
for (i=0;i<r;i++)
{
    mat[i]=malloc(c*sizeof(int));

    popuniNiz(mat[i],c);

}
int j;
for (i=0;i<r;i++)
{
     for (j=0;j<c;j++)
    {
        printf("%4d",*(*(mat+i)+j));
    }
    printf("\n");
}

    return 0;
}