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BYTEBEEEAAAAT

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Jan 23rd, 2018
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C 0.92 KB | None | 0 0
  1. #define R return
  2. t;r;k(n){R t>>n;}
  3. g(octave,note,volume){R((int)(t*(("GZkZCZkZ?ZkZ_xGxxeP<"[((k(16)%4)*4)+note%4+((k(19)&1)*(((k(16)&3)==2)*8))])/(float)(1<<octave)))%256)*volume/512.0;}
  4. m(octave,note,volume){R((int)((t*("kG_GZGPZkC_CZCPZGGG<\0GG<\000555555PPPPZZZZZ6GPk6GPk6CPk6CPkxeP<xeP<x_G<x_G<Send Nudes"[note])-(k(9)&3))/(1<<octave))%256)*volume/512.0;}
  5. n(volume,pitch,c){R((((t%pitch)==0)&&!c)?(r=rand()):r)/((1<<30)/volume*2);}
  6. s(i,a){R i>16?0:a;}
  7. j(i,a){R i>a?2*a-i:i;}
  8. main(x){for(;;t++){putchar((int)(s(g(5,k(10)%3,300),(k(19)%13)?((16-(k(12)&15))*3):0)+g(7,(k(15)*2)+((k(13)%4)>2),76)+j(g(7,0,160),40)+j(g(8,0,160),40)+n(32-((k(k(15)%4!=3?((k(14)%2)?7:8):(k(14)%4)!=3?7:8-(k(17)&1)))%32),(k(13)<24)?32-k(13)-(k(13)&1)*8:(k(13)&1?2:8),0)+j(m(5,(k(13)&31)+(k(16)%16==7)*8+(k(19)&1)*40,(((k(19)&3)!=2)&&k(20))||k(20)==1?256:0),64)+g(4,k(13),k(21)?48:0)+g(5,k(12),(k(18)%5)?48:0)+((k(19)%7)?n(16-(k(10)&15),1,1):0))/2);}}
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