How Many Nums Between 2 Positive Integers Divide To 5

using System;
class HowManyNumsBetween2PosIntDivideTo5
{
  static void Main()
  {
    //Write a program that reads two positive integer numbers and prints how many numbers p exist between them such that the reminder of the division by 5 is 0 (inclusive). Example: p(17,25) = 2.

    Console.Write("Please enter the first positive integer number:");
    string inputString = Console.ReadLine();
    uint numberOne;
    if (uint.TryParse(inputString, out numberOne)) ;
    else
    {
      Console.WriteLine("Invalid input. You should enter a positive integer number!");
    }

    Console.Write("Please enter the second positive integer number:");
    inputString = Console.ReadLine();
    uint numberTwo;
    if (uint.TryParse(inputString, out numberTwo)) ;
    else
    {
      Console.WriteLine("Invalid input. You should enter a positive integer number!");
    }

    if (numberTwo < numberOne)
    {
      Console.WriteLine("Number one should be smaller than number two!");
    }

    uint counter = 0;

    for (uint i = numberOne; i <= numberTwo; i++)
    {
      if (i % 5 == 0)
      {
        counter++;
      }
    }
    Console.WriteLine("The interval [{0}, {1}] has {2} member(s) that can be divided by 5", numberOne, numberTwo, counter);
  }
}