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MikecIT

Funkcije - 11.

Dec 1st, 2014
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C 0.27 KB | None | 0 0
  1. int rotlevo(float x[], int n, int start, int end)
  2. {
  3.     int i;
  4.     float pom;
  5.  
  6.     if(start<0 || end>n-1 || start>end) return 0;
  7.     else
  8.     {
  9.         pom=x[start];
  10.         for(i=start;i<end;i++)
  11.             x[i]=x[i+1];
  12.         x[end]=pom;
  13.     return 1;
  14.     }
  15. }
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