Вариант 9. Таск 2

#include <stdio.h>
#include <math.h>

int main() {
    double a, b, c, status = scanf("%lf%lf%lf", &a, &b, &c) == 3 && a < b && (b - a) / c == (int)((b - a) / c);

    for (double x = a; x <= b && status; x += c) {
        printf("%lf | ", x);
        if (x <= 0)
            printf("%lf", sin(exp(-pow(x, 2)) + 0.25));
        else if (x <= 1)
            printf("%lf", pow(x, 3) + fabs(x - 2.5));
        else
            printf("%lf", 2.5 * exp(0.1 * x * sin(0.01 * x)));

        printf("\n");
    }

    if (!status) printf("n/a");

    return 0;
}