15.ObjectsAndClasses-Order by Age

15.ObjectsAndClasses-Order by Age
You will receive an unknown number of lines. Each line will be consisted of an array of 3 elements. The first element will be a string and it will represent the name of a person. The second element will be a string and it will represent the ID of the person. The last element will be an integer - the age of the person. When you receive the command “End”, print all the people, ordered by age.
Examples
Input                                       Output
Georgi 123456 20                            Stefan with ID: 524244 is 10 years old.
Pesho 78911 15                              Pesho with ID: 78911 is 15 years old.
Stefan 524244 10                            Georgi with ID: 123456 is 20 years old.
End


using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace Order_By_Age
{
    class Program
    {
        static void Main(string[] args)
        {
            List<string> command = Console.ReadLine().Split().ToList();
            List<dynamic> list = new List<dynamic>();//Създаване на обект "dynamic" без да нужно създаването на "class"!

            while (command[0] != "End")
            {

                string name = command[0].ToString();
                string id = command[1].ToString();
                int age = int.Parse(command[2]);
                dynamic person = new { name, id, age };//Така се избягва стандартния начин на създаване на "class"( с пропъртита)!

                list.Add(person);
                command = Console.ReadLine().Split().ToList();

            }
            if (command[0] == "End")
            {
                var result = list.OrderBy(person => person.age);
                foreach (var item in result)
                {
                    Console.WriteLine($"{item.name} with ID: {item.id} is {item.age} years old.");
                }
            }
        }
    }
}