Limit sqrt(n)sinx

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

double limite(long int n);

int main(int argc, char const *argv[])
{
    int n=50000;
    double result;
    result = sqrt(n)*limite(n);
    printf("resultado: %f\n",result);
    return 0;
}

double limite(long int n){
    if (n==1)
        return 1;
    return sin(limite(n-1));
}