namereq

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Jun 17th, 2018
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C 0.30 KB | None | 0 0
  1. #include <stdio.h>
  2. #define N 100
  3.  
  4. int main(void)
  5. {
  6.     int i,sum37 = 0,sum21 = 0;
  7.     for(i=1;i<=N;i++){
  8.         if(i%3 == 0 || i%7 == 0){
  9.             sum37 += i;
  10.             if(i%21 == 0) sum21 += i;
  11.         }
  12.     }
  13.     printf("3の倍数または7の倍数の和:%d\n",sum37);
  14.     printf("3と7の公倍数の和:%d\n",sum21);
  15.     return 0;
  16. }
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